Fun with math paradoxes A friend just sent me a mathematical proof of 1=0 over AIM. Within 6 minutes, he had been pwned. Here's the log:
(17:16:13) LOZKing: I broke math.
(17:16:14) LOZKing: 4x²+4x+1=0
sqrt(4x²+4x+1)=sqrt0
2x+1=0
x²+2x+1=x²
sqrt(x²+2x+1)=sqrt(x²)
x+1=x
1=0
*Universe implodes*
(17:17:12) biolizard89: hang on while I absorb that
(17:20:18) biolizard89: all right, so if x^2+2x+1=x^2, then 2x+1=0, then 2x=-1, then x=-0.5
AHA, I SEE THE ERROR!
(17:20:26) biolizard89: Let's see...
(17:20:40) biolizard89: You made the mistake of thinking that sqrt(x^2) = x
(17:20:42) biolizard89: it isn't
(17:20:45) biolizard89: it's abs(x)
(17:21:12) biolizard89: So this should reduce to abs(x+1) = abs(x), which is true for x=-0.5
(17:21:29) biolizard89: Which was the only solution to the original equation
(17:21:32) biolizard89: pwned
Yeah, he didn't know why it was false. :lol: Anyone else dealt with fake math paradoxes?
fuzziqersoftware- 05-05-2006
Well, I remember a brainteaser my sister told me about these guys who had $30, split it up all different ways, put it back together, and had $29. I found out that the reason was that they subtracted $3 and added $2 in one place, so it was easily disproven.
I also remember reading a statement about how 6 * 5 = 29, and it actually did work (they used a base other than 10), but I can't find it anymore.
fuzziqersoftware- 06-04-2006
a > 0 and b > 0, but that doesn't mean that a = b.
Deadulas- 06-04-2006
all assumptions
biolizard89- 06-04-2006
Found that on some clothing website.
Props to anyone who can find the mistake.
xDThat's easy. Step 5 divides both sides of the equation by a-b, which is illegal since a=b, so a-b=0. Division-by-zero errors are probably the most common fake math paradox.
Fomar0153- 06-06-2006
See maths is flawless.
My maths teacher used to set us things like that to make us think.
Try:
3 + 4 = 12
(you have to prove it)
Solution:
It works in a number base of 5
RydiaFromFF2- 07-21-2006
Geezus! Ya'll making my head feel all dizzy wizzy @.@
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